In a ADC,the example I got was.A 2-bit ADC in a 10v range can represent this 10v analog input as 4 different binary values


Value-Voltage Resolution
00-(0-2.5v),
01-(2.5v-5v),
10-(5v-7.5),
11-(7.5v-10v)

and it divides the input voltage range into four voltages of resolution.My question is how does a 10-bit resolution,have 1024 values if you can basically only have 4 finite values of binary. 00,01,10,11.Little confused here,I tried looking it up but got more confused.

 

2-bit adc has 2 bits, 2^2=4.

10-bit adc has 10 bits, 2^10=1024.

 

You can only have 4 different values when having 2 bit resolution. When you're having 10 bits, you can have 1024 different values.

0 = 0000000000
1 = 0000000001
2 = 0000000010
3 = 0000000011
4 = 0000000100
...
1021 = 1111111101
1022 = 1111111110
1023 = 1111111111

 

One bit of binary has only two values - 0 or 1. In your 2-bit example, you have two bits, each with two possibilities (0 and 1), giving you 4 possible combinations (2^2 = 4).

N-bit data has 2^n values, so 2^10 = 1024.

 

thanks,for some reason I had convoluted thinking about how many combinations you could have. lol