Hello Forum Members,
I have come across this circuit schematic in the service guide of an old arcade machine:

I started to do some calculations but I'm not sure if I made a mistake. I tried to calculate where the current limiting turns on, i.e. the knee-current in case of foldback limiting. This was my line of thinking: The 723 will do whatever it can to keep the output voltage of the circuit at 12.1 V; Under the circumstances presented here (the voltages included in the schematic) the current across R14 is (12.3-12.1)/0,27 = 0.74A. As we can see the voltage at the CL pin (base of the current limiting internal transistor) is lower than the voltage on the CS pin (emitter of said transistor), hence the current limiting doesn't turn on). To turn the current limiting on, the voltage of CL pin has to reach a value that is 0.7V higher than the voltage on the CS pin. Since the voltage at the CS pin is held at 12.1V, the voltage on the CL pin has to be around 12.8V for current limiting to start. If we take into consideration the voltage divider presented by R11 and R13, a voltage of 12.8V is present on the CL pin when the voltage of the VO pin is about 14V. If 14V is present on the base of the external pass transistor, then its emitter voltage will be 13.4V. In this case the current through R14 is (13.4-12.1)/0.27 = 4.81A. So this should be the knee-current. Problem is that the power of R14 in this case is (13.4-12.1)x4,81 = 6.25W, more than double of its power rating, so it will burn out far before current limiting occurs. Is something wrong with my calculation or thinking?
One more thing, I tried to use the formula presented on page 5 of the uA723 datasheet for foldback current limiting. And if I put the values of the circuit into the Iknee formula, I get an even higher knee-current, 6.74A. Am I completely on the wrong track?
I'm attaching the datasheet for the uA723 regulator and the service guide of the arcade machine where the circuit schematic comes from.
Thank you for the help in advance!
I have come across this circuit schematic in the service guide of an old arcade machine:

I started to do some calculations but I'm not sure if I made a mistake. I tried to calculate where the current limiting turns on, i.e. the knee-current in case of foldback limiting. This was my line of thinking: The 723 will do whatever it can to keep the output voltage of the circuit at 12.1 V; Under the circumstances presented here (the voltages included in the schematic) the current across R14 is (12.3-12.1)/0,27 = 0.74A. As we can see the voltage at the CL pin (base of the current limiting internal transistor) is lower than the voltage on the CS pin (emitter of said transistor), hence the current limiting doesn't turn on). To turn the current limiting on, the voltage of CL pin has to reach a value that is 0.7V higher than the voltage on the CS pin. Since the voltage at the CS pin is held at 12.1V, the voltage on the CL pin has to be around 12.8V for current limiting to start. If we take into consideration the voltage divider presented by R11 and R13, a voltage of 12.8V is present on the CL pin when the voltage of the VO pin is about 14V. If 14V is present on the base of the external pass transistor, then its emitter voltage will be 13.4V. In this case the current through R14 is (13.4-12.1)/0.27 = 4.81A. So this should be the knee-current. Problem is that the power of R14 in this case is (13.4-12.1)x4,81 = 6.25W, more than double of its power rating, so it will burn out far before current limiting occurs. Is something wrong with my calculation or thinking?
One more thing, I tried to use the formula presented on page 5 of the uA723 datasheet for foldback current limiting. And if I put the values of the circuit into the Iknee formula, I get an even higher knee-current, 6.74A. Am I completely on the wrong track?
I'm attaching the datasheet for the uA723 regulator and the service guide of the arcade machine where the circuit schematic comes from.
Thank you for the help in advance!
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