Hi Gurus,
Pull up resistor is a well known concept.
Probably, after reading on this too much, I totally lost it and confused - how it works on a basic level
When we place a certain pull up resistor (R), how the actual Voltage and Current are being determined ?
The well known formula \( U=I*R \) has 2 unknown variables (U & I).
Please help understand on the following example:
Assume we have the following setup
The TTL IC has the following INPUT definitions:
While calculating, I can pick different values of V[in] and find the relevant I[in]....but how actually the setup will behave ?
(Vcc=5V; R=10K)
For convenience, from SN74LS04 datasheet:
Pull up resistor is a well known concept.
Probably, after reading on this too much, I totally lost it and confused - how it works on a basic level
When we place a certain pull up resistor (R), how the actual Voltage and Current are being determined ?
The well known formula \( U=I*R \) has 2 unknown variables (U & I).
Please help understand on the following example:
Assume we have the following setup
The TTL IC has the following INPUT definitions:
While calculating, I can pick different values of V[in] and find the relevant I[in]....but how actually the setup will behave ?
(Vcc=5V; R=10K)
Case No | V[in] (picked by me for the following calculations) | Vr (voltage dropped by R= Vcc-Vin) | I[in] (=Vr / R) |
---|---|---|---|
1 | 4.6V | 0.4V | 40uA |
2 | 4.0V | 1V | 100uA |
3 | 0.2V | 4.8V | 480uA |