I bought a pt4115 led driver module from ebay to drive 3x 1w (300mA-350mA) led chips. I would like to reduce the current to a lower value so that the LED runs a little cooler. In the datasheet of PT4115 (https://people.xiph.org/~xiphmont/thinkpad/PT4115E.pdf ) it is mentioned that the LED current can be changed by varying voltage applied to DIM pin on the IC. Can I achieve this by using resistors R1 and R2 (see attached pic) as a voltage divider ? Is this what the datasheet is trying to say ?

MOD: Added datasheet.

 

The datasheet says that the DIM pin already has a 200k pullup resistor to regulated +5V so you can DC dim the output with only a single resistor to ground.

 

You can set the current by using a different value for Rs, leaving the DIM unconnected.

 

The datasheet says that the DIM pin already has a 200k pullup resistor to regulated +5V so you can DC dim the output with only a single resistor to ground.

Does this mean I just connect a resistor from DIM pin to ground ?