simple answer, no. You got to do it using indirect means.
Impedance (resistance) is V/I=R
Just take the voltage into your circuit, divide by the current going into the input node and you get the input impedance. Same with the output. Put a 1v source at the output and divide 1v by the current into the output node and you get the output impedance.
When you plot the graphs, you have the ability to do math functions with the nodes voltages and currents, you just got to set up the equasions.
