power of signal and sidebands

Thread Starter

YoGMan

Joined Sep 20, 2017
76
Hello all, suppose we have a signal Acos(2pi f t )
power = (A/sqrt2)^2 = A^2 / 2
If we represent the same on a spectrum diagram , we get 2 bands, one at negative f and one at positive f with half the amplitude.
power = sum of power in each bands = (0.5A/sqrt2)^2 * 2 = A^2 /4
why the powers of part 1 and 2 not equal ?
 

Thread Starter

YoGMan

Joined Sep 20, 2017
76

MrChips

Joined Oct 2, 2009
35,034
I think you are misinterpreting the power spectrum.
Half of the power will be in each sideband, not half the signal amplitude.

The signal is in real time space, no negative time.
The power spectrum is in positive and negative frequencies.
 

Thread Starter

YoGMan

Joined Sep 20, 2017
76
I think you are misinterpreting the power spectrum.
Half of the power will be in each sideband, not half the signal amplitude.

The signal is in real time space, no negative time.
The power spectrum is in positive and negative frequencies.
Hello friend, really I'm confused about that. Will really help if I could get a more detailed explanation please. I know power depends on amplitude and negative frequency means rotating in the opposite direction , why the sum of powers not equal in both my calculations ?
 

MrChips

Joined Oct 2, 2009
35,034
Why do you say there is half the amplitude in the sidebands?
Work backwards. If the power in the sideband is half the total power, what would be the amplitude?
 
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