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Hello,
According to the following equations, we can calculate the power consumed P by a fan of diameter D blowing an air flow Q with a rotation speed N, according to the nominal values given by the manufacturer (Pn, Qn, Dn, et Nn):
\[ Q/Qn =(D/Dn )^3 N/Nn \]
\[ P/(Pn )=(D/Dn )^5 (N/Nn )^3 \]
For example:
Dn= 30.5
Qn= 980g/s
Nn=2250 rpm
Pn=80 W
We want to calculate the power consumed by a fan of the same series but with a different diameter D=20cm and which provides an air flow Q=100 g/s. The result is P=0.46 W.
My question is: can this power of 0.46W in practice make the fan of 20Cm diameter turn to provide the desired flow rate of 100g/s?
According to the following equations, we can calculate the power consumed P by a fan of diameter D blowing an air flow Q with a rotation speed N, according to the nominal values given by the manufacturer (Pn, Qn, Dn, et Nn):
\[ Q/Qn =(D/Dn )^3 N/Nn \]
\[ P/(Pn )=(D/Dn )^5 (N/Nn )^3 \]
For example:
Dn= 30.5
Qn= 980g/s
Nn=2250 rpm
Pn=80 W
We want to calculate the power consumed by a fan of the same series but with a different diameter D=20cm and which provides an air flow Q=100 g/s. The result is P=0.46 W.
My question is: can this power of 0.46W in practice make the fan of 20Cm diameter turn to provide the desired flow rate of 100g/s?
