I'm currently studying about transistors and I would like some guidance on this part
where an amplifier has this kind of circuit
For the DC Equivalent Circuit
The potentiometer would be a fixed resistor and the capacitor would be open and would result to a circuit of
On an AC Equivalent Circuit
the capacitor would be shorted. However I can't seem to understand fully how would the potentiometer act on this circuit.
From what I assume, it would act just like the DC equivalent circuit that is shown previously. Or it would split into two variable resistors shown below
where an amplifier has this kind of circuit
For the DC Equivalent Circuit
The potentiometer would be a fixed resistor and the capacitor would be open and would result to a circuit of
On an AC Equivalent Circuit
the capacitor would be shorted. However I can't seem to understand fully how would the potentiometer act on this circuit.
From what I assume, it would act just like the DC equivalent circuit that is shown previously. Or it would split into two variable resistors shown below