i have a doubt.in practical experiments,how do we connect preset and clear to ic chips in a bread board.from where to where..if in ic 7473 synchronous counters
Your link is defective.
If you are not using a particular input, then tie it to whichever logic level renders it inactive. Do NOT leave it unconnected!
7473 is a J-K flip flop with low active clear, not a counter. You should tie it HIGH through a pull up resistor so you retain the ability to reset.i have a doubt.in practical experiments,how do we connect preset and clear to ic chips in a bread board.from where to where..if in ic 7473 synchronous counters
Unconnected inputs will be at a voltage that is neither HIGH or LOW that could cause unpredictable operation. Tying them to an appropriate voltage prevents that.i didnt gt it
http://www.google.com/search?q=sync...40&bih=360&usg=__KqiTW7VYJfu-tRZasVW4jnNHjzE=i have a doubt.in practical experiments,how do we connect preset and clear to ic chips in a bread board.from where to where..if in ic 7473 synchronous counters
And then they act indignant when you suggest Googling for information before asking for help...For a generation born with Internet access, they display an alarming lack of Interwebz sophistication
Generally 74xxx series chips asynchronous (Set and Clear) are active low and need a pullup resistor to VCC if they are not used. 1K to 10K ohms is good. Not much of a need to calculate much. 4xxx series CMOS are usually active high and need to be grounded or a pull down resistor to ground. 10K to 100K ohms.i have a doubt.in practical experiments,how do we connect preset and clear to ic chips in a bread board.from where to where..if in ic 7473 synchronous counters
by Duane Benson
by Jake Hertz
by Duane Benson