Please is there any error with this schematic diagram.. The diagram is all about converting 220ac to 24dc, from the 24dc output into a lm317ic voltage regulator of 12 voltage as out put in to a 12volt battery with a battery level indicator connected to it, then from the 12volt battery into a voltage doubler.. so I don't know if there's any error and if it can be converted into a PCB design..

 

If I read correctly you have a 24Vac transformer secondary.
That will give about 32Vdc rectified, which will dissipate a lot of power when dropped by the LM317 regulator to 12V (voltage difference times the current).
Thus, for example, with a 1A output, the LM317 dissipation would be about 20W, which will require a large heatsink.

It would be better to use a transformer with a 12Vac or 15Vac secondary to reduce that dissipation.

How much load current will the doubler see?
Doublers are usually for low current.

If you want 24Vdc out, why not use a 24V battery?

You voltage indicator will not work, since both ends are connected to the +12Vdc battery voltage.
One end needs to go to ground.

 

I'd put the fuse before the power switch.


LM317 aren't guaranteed to regulate with less than a 10mA load. If you use 120 ohms for the current set resistor, you don't need to worry about that.

You don't need to use dashed lines or wire breaks when you use connection dots. Having the ground wire from your battery indicator stop at the regulator output can be confusing. Putting connection dots on terminals and having terminals on the corners of the symbol with connection dots is distracting.

Logic symbols are more useful when you have inputs mostly on the left and outputs on the right and you label all of the pin functions.

What is the battery chemistry and what voltage range to you plan to use from the voltage regulator?

How is the battery level indicator supposed to work? I didn't bother trying to analyze because you drew it sideways.

 

If I read correctly you have a 24Vac transformer secondary.
That will give about 32Vdc rectified, which will dissipate a lot of power when dropped by the LM317 regulator to 12V (voltage difference times the current).
Thus, for example, with a 1A output, the LM317 dissipation would be about 20W, which will require a large heatsink.

It would be better to use a transformer with a 12Vac or 15Vac secondary to reduce that dissipation.

How much load current will the doubler see?
Doublers are usually for low current.

If you want 24Vdc out, why not use a 24V battery?

You voltage indicator will not work, since both ends are connected to the +12Vdc battery voltage.
One end needs to go to ground.

Okay I see, thank you... your information is really helpful, I'm going to use a transfer of 220ac to 24 dc.. then change the 12volt battery to 24, and in order for the lm317 if not to get overheated Bec now they will be less voltage drop and no need of applying a voltage doubler since the out from the battery will be at the range of 24dc out put..

 

Okay thank you for the correction of my drawing, and the battery is of 12. Using the lm317ic to regulate The 24dc to about 12dc for the battery..

to the
View attachment 260601
I'd put the fuse before the power switch.

View attachment 260602
LM317 aren't guaranteed to regulate with less than a 10mA load. If you use 120 ohms for the current set resistor, you don't need to worry about that.
View attachment 260603
You don't need to use dashed lines or wire breaks when you use connection dots. Having the ground wire from your battery indicator stop at the regulator output can be confusing. Putting connection dots on terminals and having terminals on the corners of the symbol with connection dots is distracting.

Logic symbols are more useful when you have inputs mostly on the left and outputs on the right and you label all of the pin functions.

What is the battery chemistry and what voltage range to you plan to use from the voltage regulator?

How is the battery level indicator supposed to work? I didn't bother trying to analyze because you drew it sideways.

 

the battery is of 12. Using the lm317ic to regulate The 24dc to about 12dc for the battery..

Are you planning to charge the battery?

 

You have nothing to limit/control the current drawn by the battery. If the battery were low on charge when power is turned on, that could be a problem.

 

Yes

Are you planning to charge the battery?
[/QUOTE
Yes, the circuit is like a UPS.. the battery is to reserve some energy, then later give it out to a load of about 20 volt..

 

And further, the mains ON LED will glow, whether or not the Mains is ON, thanks to the Battery and the diode across LM317.

 

And further, the mains ON LED will glow, whether or not the Mains is ON, thanks to the Battery and the diode across LM317.

Please do you mean the charging indicator or the battery level indicator??

 

Please do you mean the charging indicator or the battery level indicator??

Whatever you term that LED next to the Bridge Rectifier

 

And further, the mains ON LED will glow, whether or not the Mains is ON, thanks to the Battery and the diode across LM317.

Please do you mean the

Whatever you term that LED next to the Bridge Rectifier

If it's the led after the bridge rectifier before the lm317ic is the charging indicator.. and is there anything wrong about it if not mind me asking??
charging indicator or the battery level indicator??

 

The charging indicator will be lit by the battery even when there is no mains supply.
The protection diode across the LM317 will be forward biased and will feed the charge indicator.
You will need to introduce a Blocking Diode between the LM317 output and the remaining part of the circuit. The blocking diode also will make the protection diode across the 317 redundant.

 

Yes

Regardless of battery chemistry, which you still haven't provided, all 12V batteries will require a voltage higher than 12V to charge them.

 

The charging indicator will be lit by the battery even when there is no mains supply.
The protection diode across the LM317 will be forward biased and will feed the charge indicator.
You will need to introduce a Blocking Diode between the LM317 output and the remaining part of the circuit. The blocking diode also will make the protection diode across the 317 redundant.

View attachment 260631

Ohh okay, thank you I really appreciate your contribution.. I'm going to make the correction on my diagram too..

 

Regardless of battery chemistry, which you still haven't provided, all 12V batteries will require a voltage higher than 12V to charge them.

Okay meaning they require up to 14 volt?? And here is the battery..

 

Okay meaning they require up to 14 volt??

Lead acid batteries aren't charged at a single voltage (per cell). You start off charging hard enough to prevent sulfation buildup, then you switch to trickle charging.

https://batteryuniversity.com/article/bu-403-charging-lead-acid

 

..... and as is clear from the battery label you must find a way of keeping the initial charge current less than 1.35A.