There are 3 sides to a triangle.
One side is 5"
One side is 4"
One side is 3"
The phase angle (Theta) formula is:
Tan-1 opposite over adjacent
equals tan-1 4/3
How did they get the phase angle of 53.13
I am putting it in the calculator wrong.
I am trying to get the phase of 6280(XL) over 5000(R)
Is it tan-1 6280/5000
The answer key says it's .898
???
I seem to be missing something.
One side is 5"
One side is 4"
One side is 3"
The phase angle (Theta) formula is:
Tan-1 opposite over adjacent
equals tan-1 4/3
How did they get the phase angle of 53.13
I am putting it in the calculator wrong.
I am trying to get the phase of 6280(XL) over 5000(R)
Is it tan-1 6280/5000
The answer key says it's .898
???
I seem to be missing something.