if you really want to ensure that there are no rapid transients, all you really need to do is add a 10 ohm resistor between the current supply and the circuit i posted above, and a 1uf cap from the output side of the resistor to ground. that will remove the possibility of high frequency transients due to the rc time in conjunction with the constant current supply. with no output load, it will take roughly 1.04ms to charge a 1uf cap through a 10 ohm resistor up to 62 volts with a 60ma supply, or 60v per millisecond, or 1 volt per 16.666...microsecond.
of course, adding a capacitor in the circuit will cause your project to have only an average of 60ma current through it. if the resistance of your project should decrease at a very rapid rate, the 1uf capacitor would discharge it's stored power through your load. in order to avoid that, you could add a 2nd current limiter circuit on the output of the voltage clamp circuit.
or, you could really avoid all of this by simply using a power supply where you can set the voltage and limit the output current to 60ma, rather that one that has an impractically high limit. as it is, having the voltage clamp after the current supply is a bit like having the cart before the horse. usually, when building a linear power supply, the voltage regulation comes first, with the current limiter circuitry afterwards. that's because the voltage regulation circuit uses large caps on it's output to lower it's impedance. an ideal voltage supply looks like it has zero impedance to the load. a current supply is opposite; it looks like it has infinite impedance to the load. therefore, a good current regulator should not have capacitors on it's output.
in this circuit, we have to deal with a large, slow transistor due to the amount of power that may be dissipated across it. adding a capacitor will cause current regulation to not be stable if the load resistance is not stable. however, i don't know precisely you need your current to be regulated.
adding a 65v mov should suppress rapid transients. however, movs also have some capacitance. you would need to read the datasheet for the particular mov you are considering to determine how much it will have.
of course, adding a capacitor in the circuit will cause your project to have only an average of 60ma current through it. if the resistance of your project should decrease at a very rapid rate, the 1uf capacitor would discharge it's stored power through your load. in order to avoid that, you could add a 2nd current limiter circuit on the output of the voltage clamp circuit.
or, you could really avoid all of this by simply using a power supply where you can set the voltage and limit the output current to 60ma, rather that one that has an impractically high limit. as it is, having the voltage clamp after the current supply is a bit like having the cart before the horse. usually, when building a linear power supply, the voltage regulation comes first, with the current limiter circuitry afterwards. that's because the voltage regulation circuit uses large caps on it's output to lower it's impedance. an ideal voltage supply looks like it has zero impedance to the load. a current supply is opposite; it looks like it has infinite impedance to the load. therefore, a good current regulator should not have capacitors on it's output.
in this circuit, we have to deal with a large, slow transistor due to the amount of power that may be dissipated across it. adding a capacitor will cause current regulation to not be stable if the load resistance is not stable. however, i don't know precisely you need your current to be regulated.
adding a 65v mov should suppress rapid transients. however, movs also have some capacitance. you would need to read the datasheet for the particular mov you are considering to determine how much it will have.