So (Vi - V2) / R would appear to be the current flowing downward in the righthand R, while (V2 - V1) / R is the current flowing downward in the R just below it. That seems just fine.It says: (Vi - V2)/R = (V2 - V1)/R
And from there I got: Vi + V1 = V2
So it is not correct?
I got:So what do you now get for the final answer to the problem?
That's correct, but it's a bit more complicated than it needs to be. See if you can't clean it up just a bit.I got:
Vo = (R1+R2)/(2*R2) * [1-(R+ΔR)/R] * Vi
Hi,I got:
Vo = (R1+R2)/(2*R2) * [1-(R+ΔR)/R] * Vi
Hi,
Hi,
Yes that is obviously correct. I must have copied his equation incorrectly. What i think happened was the two square brackets did not get interpreted correctly with the software. In any case though, i will correct my previous post a little later today as his solution looks correct now.
Thanks for posting.
Also that's not a bad idea posting the image of the equation rather than the typed out equation or the Tex equation or whatever is being used now.
Yes, I know. I was writing through the phone so I couldn't upload the picture. When I am on the PC I upload it, of course.Hi,
Yes that is obviously correct. I must have copied his equation incorrectly. What i think happened was the two square brackets did not get interpreted correctly with the software. In any case though, i will correct my previous post a little later today as his solution looks correct now.
Thanks for posting.
Also that's not a bad idea posting the image of the equation rather than the typed out equation or the Tex equation or whatever is being used now.
Hi again,Yes, I know. I was writing through the phone so I couldn't upload the picture. When I am on the PC I upload it, of course.
Thanks everyone!
by Aaron Carman
by Jake Hertz
by Jake Hertz