One question which would help answer this is what is this circuit supposed to do, and what is the intended range of load impedance....
BTW, I disagree that this circuit is impractical ...
We already see that a high impedance load is impractical for two reasons. First, high impedance is likely to be marginally stable and prone to tolerance problems. Second, t_n_k has shown that a high impedance load results in a voltage gain equation consistent with a voltage source; and, we really don't want a high impedance voltage source.
If we consider the voltage gain equation with a finite (and relatively low) value of load impedance \( R_L \), under the condition that source impedance is set to infinity we get the following, assuming everything is perfectly balanced.
\( G={{R_3 R_5 R_L}\over{ R_2 R_4 R_6 }}\)
This is a voltage source with voltage proportional to load resistance. Or, in other words it's a good current source. Hence, at this point I'm inclined to agree with you that this is likely a practical circuit. I think to be sure, one needs to do a sensitivity analysis to see how resistor tolerance will affect the results. It seems that stability is not an issue, but the quality of the current source might be sensitive to tolerances.
For reference the full voltage gain formula works out to the following.
\( G={{R_1 R_3 R_5 R_L}\over{ R_2 (R_4 R_6 R_1 + R_4 R_6 R_L + R_4 R_1 R_L - R_5 R_3 R_L) }}\)
A sensitivity analysis can be done using this equation.