Hi,

I am learning NPN transistor characteristics by changing the supply polarities.

There are two circuits below.

1. I forward biased the BE and reverse biased the CB junctions. I see the following VBE vs IC Char. (also I don't understand the slope, please explain?)


2. I reverse biasing the BE and forward bias the CB junctions, I still see similar amount of current (-ve)



What is happening in these circuits, what is the slope in first plot, which one is right, when to use what? More details. Please.

 

What is right for what purpose?

The base-emitter conjunction looks like a normal p-n diode junction. When it is reversed biased, there is very little B-E current.
The base-emitter conjunction needs to be forward bias. When that happens you get collector-emitter current flow.

 

A BJT will operate as a transistor with the emitter and collector connections reversed, just with a much lower gain.
That's what you see in the second simulation.

 

The slope is because of the resistor value I used. But in my simulation here where I am stepping the rc resistor from 10 to 100 Ohms. How is there a -ve voltage at the collector (vc) when my VCC supply is positive.