So I first find the Thevenin's resistance:
3kΩ ll 6kΩ = 2kΩ
2kΩ + 2kΩ = 4kΩ
4kΩ + 4kΩ = 8kΩ
8kΩ ll 8kΩ = 4kΩ
Rth = 4kΩ
Then I tried to find the shortcircuit current:
( 8kΩ / ( 8kΩ + 4kΩ + 2kΩ + 6kΩ ll 3kΩ) ) 2mA = ( 8kΩ / 8kΩ ) 2mA = 2mA
isc = 2mA
But I still have a feeling that this is wrong some how, any idea?
3kΩ ll 6kΩ = 2kΩ
2kΩ + 2kΩ = 4kΩ
4kΩ + 4kΩ = 8kΩ
8kΩ ll 8kΩ = 4kΩ
Rth = 4kΩ
Then I tried to find the shortcircuit current:
( 8kΩ / ( 8kΩ + 4kΩ + 2kΩ + 6kΩ ll 3kΩ) ) 2mA = ( 8kΩ / 8kΩ ) 2mA = 2mA
isc = 2mA
But I still have a feeling that this is wrong some how, any idea?
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