So there's a question in a book asking to solve a circuit using Norton's theorem and I've only been able to solve it using superposition. (Circuit attached)
So to solve using superposition here's what I did, I opened the current source and calculated 12V across R1 and 8V across R2, simple series circuit. Next I shorted the voltage source and calculated 6V across both resistors, simple parallel circuit. Then adding and subtracting the values I get 18V across R1 and 2V across R2 and this makes sense.
But how can I calculate using Norton's theorem, It may not be the best method but I'd like to learn.
Thanks
Edit: Forgot to mention that the 1mA source is actually an unknown resistor but has 1mA running through it.
So to solve using superposition here's what I did, I opened the current source and calculated 12V across R1 and 8V across R2, simple series circuit. Next I shorted the voltage source and calculated 6V across both resistors, simple parallel circuit. Then adding and subtracting the values I get 18V across R1 and 2V across R2 and this makes sense.
But how can I calculate using Norton's theorem, It may not be the best method but I'd like to learn.
Thanks
Edit: Forgot to mention that the 1mA source is actually an unknown resistor but has 1mA running through it.
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