I'm writting some code for PIC uC using XC compiler, we can use macro NOP() for an empty instruction to execute, I believe it will take one cycle?
if uC is configured with 4Mhz clock how can I calculate duration that NOP instruction may take?

 

I believe it will take one cycle?

One instruction cycle.

Which is 4 clock cycles.

 

One instruction cycle.

Which is 4 clock cycles.

Sorry not good in math, that means 4 / 4,000,000 = 0.000001 uS
is that right?

 

Sorry not good in math, that means 4 / 4,000,000 = 0.000001 uS
is that right?

YES! But, it is hardly worthy of the name MATH -- more like Arithmetic.

 

Sorry not good in math, that means 4 / 4,000,000 = 0.000001 uS
is that right?

No. Your units are wrong. It 4/4MHz = 1μs.

 

No. Your units are wrong. It 4/4MHz = 1μs.

One more thing if I use 8Mhz clock instructions still would be 4, so 4 / 8MHz = 5ns

 

Hello,

No, 4 ticks at 8 MHz is 500nS or 0.5 uS

Bertus

 

It is really simple. When you invert a frequency in Hz, the answer is in seconds. When you invert a frequency in MHz the answer is in 1/1,000,000th seconds, or microseconds. Nanoseconds would pair with GHz.