I have a few questions i missed and scored a 69 on my lesson. this is one point below passing grade of 70. i need help with the questions i missed. i have been rereading this lesson over and over but cannot seem to locate the correct answers. i am going to post the questions here, i hope someone can help me out.
Question 26 (which i did get right) is
*A step voltage of 15 volts is applied to a 100 ohm resistor in series with a 2-H inductor. The initial current rise (near time 0) equals.
(1) 0.133 A/s
(2) 0.15 A/s
(3) 6.67 A/s
(4) 7.50 A/s (my answer)
(5) none of these
Questions 27 to 32 refer to the circuit of question 26 (the following questions are the ones i am having issue with)
Question 28) the steady state value of voltage across the inductor is (if i could figure this one out i think the rest will fall into place)
(1) 0 V (i think steady state voltage should be "0" across the inductor at least that is what the math appears comes out to) (only thing is the circuit specifies a step voltage which is confusing me a little when they ask for steady state here.)
(2) 0.15 V
(3) 6.67 V
(4) 7.5 V
(5) 15 V (my answer)
Question 29) the initial value of voltage across the inductor is
(1) 0 V (my answer)
(2) 0.150 V
(3) 6.67 V
(4) 7.50 V
(5) 15 V (i think this might be the correct answer on this one)
Question 31) After one time constant the voltage across the inductor is.
(1) 5.5 V
(2) 6.3 V
(3) 4.5 V (my answer)
(4) 9.5 V
(5) 15 V
question 32) after one time constant the current through the inductor is.
(1) 37 mA
(2) 63 mA
(3) 55 mA
(4) 95 mA (i think this should have been the correct answer)
(5) 150 mA (my answer)
Question 33) A 1000 V step is applied across a 400 k ohm resistor in series with a 2uf capacitor. the initial rate of rise of voltage across the capacitor is found by V divided by T, where T= R x C. the initial rate of rise is. (i did get this one right)
(1) 0.25 v/s
(2) 500 V/s
(3) 1000 V/s
(4) 1250 V/s (my correct answer)
question 34) the steady state value of voltage across the resistor, question 33, is
(1) 0 V
(2) 500 V
(3) 1000 V (my Answer)
(4) 1250 V
any help would be greatly appreciated.
thanks,
Question 26 (which i did get right) is
*A step voltage of 15 volts is applied to a 100 ohm resistor in series with a 2-H inductor. The initial current rise (near time 0) equals.
(1) 0.133 A/s
(2) 0.15 A/s
(3) 6.67 A/s
(4) 7.50 A/s (my answer)
(5) none of these
Questions 27 to 32 refer to the circuit of question 26 (the following questions are the ones i am having issue with)
Question 28) the steady state value of voltage across the inductor is (if i could figure this one out i think the rest will fall into place)
(1) 0 V (i think steady state voltage should be "0" across the inductor at least that is what the math appears comes out to) (only thing is the circuit specifies a step voltage which is confusing me a little when they ask for steady state here.)
(2) 0.15 V
(3) 6.67 V
(4) 7.5 V
(5) 15 V (my answer)
Question 29) the initial value of voltage across the inductor is
(1) 0 V (my answer)
(2) 0.150 V
(3) 6.67 V
(4) 7.50 V
(5) 15 V (i think this might be the correct answer on this one)
Question 31) After one time constant the voltage across the inductor is.
(1) 5.5 V
(2) 6.3 V
(3) 4.5 V (my answer)
(4) 9.5 V
(5) 15 V
question 32) after one time constant the current through the inductor is.
(1) 37 mA
(2) 63 mA
(3) 55 mA
(4) 95 mA (i think this should have been the correct answer)
(5) 150 mA (my answer)
Question 33) A 1000 V step is applied across a 400 k ohm resistor in series with a 2uf capacitor. the initial rate of rise of voltage across the capacitor is found by V divided by T, where T= R x C. the initial rate of rise is. (i did get this one right)
(1) 0.25 v/s
(2) 500 V/s
(3) 1000 V/s
(4) 1250 V/s (my correct answer)
question 34) the steady state value of voltage across the resistor, question 33, is
(1) 0 V
(2) 500 V
(3) 1000 V (my Answer)
(4) 1250 V
any help would be greatly appreciated.
thanks,