Makes no sense because 4 hours is not the same as ~4 hours...

so..it is nearly equal in some sec may be.

 

0.6166+X*0.1833=1
616/100+X*183/100=1
X*183/100=1-616/100
like this we get
x=2+98/100

Please consider the following with attention to use of "~" and "=":

x=2+2+1/11 = 4+1/11 Hours
Hence the task completed at ~ 1:00 PM

 

Two cars are traveling at 60 mph and 45 mph respectively. If the faster car travels two hours longer and twice as far, then:
What are the distances traveled by each car?
What are the operation times of each car?
If the faster car travels two hours longer and twice as far, then:
Ta+2 hours
Da+2

 

Prior to moving on, do you understand the lessons of the last exercise?

 

Prior to moving on, do you understand the lessons of the last exercise?

That machine one?
it was easy.

 

That machine one?
it was easy.

To summarize:
--Do not correlate unequal values with "="!
--Do not express non-integral values via expansions!

OK?

 

Two cars are traveling at 60 mph and 45 mph respectively. If the faster car travels two hours longer and twice as far, then:
What are the distances traveled by each car?
What are the operation times of each car?
If the faster car travels two hours longer and twice as far, then:
Ta+2 hours
Da+2

 

@RRITESH KAKKAR

Time for me to sign off for the nonce (Zzzzzzz)--- Please ask @WBahn how he wishes you to approach the problem -- Not being 'raised' on the 'unit tracking' technique myself - I am not an ideal teacher of said practice (Please note that @WBahn is a Bona Fide instructor! -- Hence, if he advises that tracking units is good practice - you can bet on it!) --- So please work on it -- I'll look in tomorrow at the same time

If you're experiencing difficulty or if @WBahn was unavailable I'll assist you with the exercise --- FWIW My purpose in posting that particular exercise was/is to encourage your adoption of the 'simultaneous solution' approach -- so please 'tend to that' as well!

Chat with you tomorrow...

Very best regards
HP

 

how to solve this problem?

 

nonce (Zzzzzzz)

??

 

For What It's Worth FWIW

 

how to solve this problem?

Please ask @WBahn to guide you in your approach to the problem --- Otherwise I'll help you with it tomorrow!

??

Just a silly way of saying 'Time for me to get my rest'

Best regards
HP

 

For What It's Worth FWIW

Correct! -- Now I really must go! --- See you tomorrow!

 

Two cars are traveling at 60 mph and 45 mph respectively. If the faster car travels two hours longer and twice as far, then:
What are the distances traveled by each car?
What are the operation times of each car?
If the faster car travels two hours longer and twice as far, then:
Ta+2 hours
Da+2

"Ta + 2 hours" is just an expression and, by itself, doesn't convey any information. You need to establish relationships between the various variables using equations, not expressions.

Since you are somewhat on the right track, I will give you the first one:

"Car A travels two hours longer than Car B" translates to "Ta = Tb + 2 hours". Since I said that I didn't want you using numerical quantities until the end, we use Td for the amount of time by which Car A travels in excess of the time traveled by Car B. So "Ta = Tb + Td".

Now you translate "Car A travels twice as far as Car B" to get an equation involving Da and Db.

 

Ta = Tb + 2
Ta = Tb + Td
Tb + 2=Tb + Td

D=S*T
What are the distances traveled by each car?
Da=Sa*Ta
Da=60*Tb + 2
Db=Sb*Tb
Db=45*Tb

 

@HP, your no longer an "angel", your now approaching sainthood.

 

Ta = Tb + 2
Ta = Tb + Td
Tb + 2=Tb + Td

D=S*T
What are the distances traveled by each car?
Da=Sa*Ta
Da=60*Tb + 2
Db=Sb*Tb
Db=45*Tb

UNITS !!!!!!!

ORDER OF OPERATIONS !!!!!!!!

SYMBOLIC ONLY !!!!!!!!

If you have

Da = 60*Tb + 2

what you really have, because of order of operations, is

Da = (60*Tb) + 2

and you will end up with the wrong answer and be scratching your head wondering where things went wrong. As you work more complex problems you simply can't rely on "knowing what I meant" to avoid the consequences of sloppy math.

If you track your units, you would see, at some point, that

Da = (60 mph * Tb) + 2 hours

results in 'distance' + 'time', which makes no sense. And this nonsense would propagate itself through your work until it slapped you upside the head and forced to realize that you had made a mistake and it would then provide a roadmap right back to where the mistake was made, allowing you to correct this to

Da = 60 mph * (Tb + 2 hours)

and then work forward from there instead of having to start over from scratch.

But, having pointed all of that out, I told you that I don't want to see any numbers until you are ready to get the final answers. So at this point you should have:

Ta = Tb + Td
Da = Sa*Ta = Sa*(Tb + Td)

You have four unknowns, Ta, Tb, Da, Db, so you need four (independent) equations. You have two. The first is from the constraints given in the problem involving the times and the second is from D=S*T for Car A. So get a third from the constraints given in the problem involving the distances and a fourth from D=ST for Car B.

 

@HP, your no longer an "angel", your now approaching sainthood.

My beatification as I live and breathe -- Golly, Golly!!!

 

My beatification as I live and breathe -- Golly, Golly!!!

Is it just me, or does it seem strange that the root of beatification is "beat"?

(and, yes, I know that it is really Latin "beatus" -- but that begs a similar question of whether "beating someone" means you are blessing them. )

I think I will tell my daughter next time she gets in trouble that she is headed for a "blessed beating"!

 

@RRITESH KAKKAR
As an aside -- Once having properly stated the equations in the unknowns - please recall that simultaneous solution requires inclusion of all said expressions! --- Hence, if you will be solving via substitution, you must select one unknown then 'combine' all equations 'in terms' of same --- Alternately, you may solve (simultaneously) via 'cancellation' (the preferred method, IMO).

One caveat: While said approaches are readily applicable to 1'st degree equations - care must be exercised with non-linear expressions - lest complication owed to extraneous and/or 'lost' solutions become manifest!

Hint: As regards the current exercise - simultaneous solution will be straightforward!

Best regards
HP