hi
i have searching on for more problems to help me with the op amp especially with slew rate
i found these problems and i couldn't solve them can you please help me

i couldn't understand the solution or how was it found

also this problem i didn't know how to solve it

 

please can anyone help me

 

In my day, if you didn't know an answer you just accepted that you got that one marked incorrect.

 

In my day, if you didn't know an answer you just accepted that you got that one marked incorrect.

but it is not a homework i found it on the internet

 

hi Ghina,
Look thru this AAC Article, it may help.
https://www.allaboutcircuits.com/technical-articles/understanding-operational-amplifier-slew-rate/

also these Tutorial Videos
https://www.google.com/url?sa=t&rct=j&q=&esrc=s&source=web&cd=&cad=rja&uact=8&ved=2ahUKEwj45oeR5aLrAhX1UhUIHf3aCYIQwqsBMAt6BAgKEAQ&url=https://www.youtube.com/watch?v=2DFIr6t1hbc&usg=AOvVaw2oUrRiGSXGVEu-BtXuFNyl
E

 

The maximum slew rate of a sinewave is the derivative of the function ia as stated in the problem:



Thus you plug the known values into the formula (dV/dt = Vm*2πf) to find the unknown, where dV/dt is the slew-rate, Vm is the peak value of the sinewave, and f is it's frequency.
You do know how to solve for an unknown in such an equation?

 

The maximum slew rate of a sinewave is the derivative of the function ia as stated in the problem:

View attachment 214982

Thus you plug the known values into the formula (dV/dt = Vm*2πf) to find the unknown, where dV/dt is the slew-rate, Vm is the peak value of the sinewave, and f is it's frequency.
You do know how to solve for an unknown in such an equation?

of course i know how to solve such equation but actually i don't understand how it was derived
it is easy to find the maximum frequency for a given slew rate and Vm but i don't know i find it complicated to solve for Vm i feel like i'm missing something so i don't understand how this came

 

hi Ghina,
Look thru this AAC Article, it may help.
https://www.allaboutcircuits.com/technical-articles/understanding-operational-amplifier-slew-rate/

also these Tutorial Videos
https://www.google.com/url?sa=t&rct=j&q=&esrc=s&source=web&cd=&cad=rja&uact=8&ved=2ahUKEwj45oeR5aLrAhX1UhUIHf3aCYIQwqsBMAt6BAgKEAQ&url=https://www.youtube.com/watch?v=2DFIr6t1hbc&usg=AOvVaw2oUrRiGSXGVEu-BtXuFNyl
E

thank you it is actually helpful but i didn't find what i'm looking for

 

i know how to solve such equation but actually i don't understand how it was derived

The rate-of-change of a function is found by taking it's derivative.
Thus you take the derivative of the sine function to get its rate-of-change (slew-rate).
The derivative maximum occurs when the COS equals 1.
What's difficult about that?

 

The rate-of-change of a function is found by taking it's derivative.
Thus you take the derivative of the sine function to get its rate-of-change (slew-rate).
The derivative maximum occurs when the COS equals 1.
What's difficult about that?

ok i'll solve it here and if u please show me what is wrong with my answer
dv/dt = Vp 2pi f cos(2pi f t )
T= 1/f = 1us and t at Vp = 0.5us since it is symmetrical wave then cos(2pi f t)=1
=> dv/dt = vp 2pi f
5v/1us = vp 2pi 1M
and when i solve for vp it is equal to 0.79v NOT 5/2 so where did i make a mistake