i actually have found this particular formula in my text bk,thanks a lot

OK, so the method of substitution says that if u is some function of x, and you can compute an expression for du then:

\(\int \; \frac{1}{u} \; du\; =\; ln(u) \; + \; C\)

 

I find it hard to believe that:

\(\int \; \frac{1}{x} \; dx \; =\; ln(x) \; + \; C\)

is not there. All of mine do!

I found them, numbers 13 and 16: http://integral-table.com/downloads/single-page-integral-table.pdf

 

There is certainly nothing fundamentally wrong with the approach that you proposed. Of course you also need to arrive at the same result since the solutions to all integration problems are unique: neglecting the arbitrary constant of course.

 

I found them, numbers 13 and 16: http://integral-table.com/downloads/single-page-integral-table.pdf

Thanks a lot for this table of integrals,its absolutely helpful now and going forward with my studies.

 

Thanks a lot for this table of integrals,its absolutely helpful now and going forward with my studies.

Normally calculus textbooks have tables like that. However, as I learned today, the tables in the textbook can be tailored to the textbook, and not contain some integrals.