BobaMosfet
- Joined Jul 1, 2009
- 2,211
that's why I said 'like'.... Doesn't matter how much current you're measuring, you can do it with an inductive coil (even in the DC domain if you know what you're doing).That device is only rated up to 20A.
that's why I said 'like'.... Doesn't matter how much current you're measuring, you can do it with an inductive coil (even in the DC domain if you know what you're doing).That device is only rated up to 20A.
use a a hall-effect sensor premade, or you can engineer your own if you work on it:Hello,
I am trying to measure high current and I do not have a measurement device rated high enough to directly measure 180A, is this a good method? ----> I was reading about the use of shunt resistors connected in parallel with multimeters and although the multimeter may not be rated for 180A, it could still measure the current indirectly by putting it on the voltage setting and measuring the voltage drop across the shunt resistor. Since the internal resistance is so high compared to the shunt resistor the multimeter wouldn't see anywhere near the 10A fuse rating. The shunt resistor I have says 500A and 50mV on it so I assume it has a resistance of 0.1 milliohm. The multimeter I have is a fluke 117 true rms multimeter and after looking online it looked like the internal resistance was roughly 10Mohms. My reasoning is below:
Side note: Also I am curious, would I need special test leads or can I use what came with the fluke?
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