ArakelTheDragon
- Joined Nov 18, 2016
- 1,366
Is it not 6V x √2 = 8.5V ?
Last time I checked, that is the correct answer, rounded to one decimal place.Is it not 6V x √2 = 8.5V ?
Not the last time I looked - unless you want to compare the input signal to 0V.One of the input resistors needs a ground connection for the LM339's input bias current.
You don't need the 10k output resistor.
The current is already limited by the 10k resistor to +5V.
What part of my post are you referring to?Not the last time I looked - unless you want to compare the input signal to 0V.
Sorry - but I've seen otherwise in functional commercial products.What part of my post are you referring to?
Certainly the inputs needs a DC path to ground, (the last time I looked).
I'd like to see how they do it without a DC path to ground for the input, as all comparators and op amps need such a path..Sorry - but I've seen otherwise in functional commercial products.
Anything with rail to rail common mode doesn't care where its inputs are - some don't like them to be too far apart though.I'd like to see how they do it without a DC path to ground for the input, as all comparators and op amps need such a path..
True, they don't care where the inputs are within the rail voltages under normal operating conditions.Anything with rail to rail common mode doesn't care where its inputs are - some don't like them to be too far apart though.
Don't need to - seen a few commercial applications that already did it.True, they don't care where the inputs are within the rail voltages under normal operating conditions.
But if they don't have a path for the input bias currents, then the inputs will go to one of the rails (depending upon the direction of the bias current) and the circuit will be saturated and not work.
If you don't believe give it a try with a real circuit.
If your comparator is working correctly - the output is a square wave and the mean of the waveform is an entirely different equation.I was pretty certain I saw 5V is 8.5V peak to peak. That is why I asked!
Well if they truly have no DC path for the input bias current, they won't work.Don't need to - seen a few commercial applications that already did it.
If you say so.Well if they truly have no DC path for the input bias current, they won't work.
I believe I did, yes.If you say so.
You usually do...……..I believe I did, yes.

Huh. I have not found that to be true in practice. I recall having to raise my reference point a few mV above ground. Rereading datasheet now...Just like it, its input common mode range extends below its negative rail, so GND can be use as a comparator trip point.
Thinking more about the problem I had to solve, I think it was simply that I wanted to switch at 0V as you said. The switching was unreliable until I raised the other pin a few millivolts above ground.Vee - 0.3 V (from memory). In practice, both the 393 and 358 have essentially identical PNP input stages, so it makes sense that things fall apart at Vee - 0.6 - ish. A common circuit to monitor a negative voltage with a positive-voltage-only monitoring system is to create a voltage divider from the positive reference voltage to the negative input, with 0 V as the trip point for the comparator. Been doing it for decades.
ak