Hello All,
I have an interest in moving some of my LED lighting applications away from logic-level MOSFET designs and instead using step-up boost converters designed as LED drivers. I have to admit that once I started digging through datasheets and information about these little ICs, they seem more complicated than I first imagined, especially in trying to understand how to select the proper values for the inductor and the Schottky Barrier Diode. I have been reading documents from TI and Toshiba, among others on this topic and I appear to be having trouble with the math and cannot figure out why, so I am looking for a little help.
In the document from TI, titled Schottky Diode Selection in Asynchronous Boost Converters, which (obviously) applies to selecting an appropriate SBD, the following is given:

I am following these formulas using the given example values and the result I'm getting is not 0.749A. Here are my results:
\( D = \frac{V_{outmax} - V_{inmin} * efficiency}{V_{outmax}} \)
\( D = \frac{26.7 - 2.7 * 0.87}{26.7} \) \( D = \frac{26.7 - 2.349}{26.7} \) \( D = \frac{24.351}{26.7} \) \( D = 0.912 \)
\( \Delta I_L = \frac{V_{in} * D}{f_{SW} * L} \)
\( \Delta I_L = \frac{26.7 * .912}{1,000,000 * .00001} \) \( \Delta I_L = \frac{24.351}{10} \) \( \Delta I_L = 2.4351\)
\( I_{L(PEAK)} = (\frac{I_{LED(TOTAL)}}{1 - D} + \frac{\Delta I_L}{2}) \)
\( I_{L(PEAK)} = (\frac{.06}{1 - .912} + \frac{2.4351}{2}) \) \( I_{L(PEAK)} = (\frac{.06}{.088} + \frac{2.4351}{2}) \) \( I_{L(PEAK)} = (.6818 + 1.21755) \)
\(I_{L(PEAK)} = 1.9A \)
I'm certain I have to be doing something wrong in my math, I'm so far off from the example result. I want to get the same result as in the example so I'm confident in calculating these values for the circuit I'm currently working on.
Thank you
I have an interest in moving some of my LED lighting applications away from logic-level MOSFET designs and instead using step-up boost converters designed as LED drivers. I have to admit that once I started digging through datasheets and information about these little ICs, they seem more complicated than I first imagined, especially in trying to understand how to select the proper values for the inductor and the Schottky Barrier Diode. I have been reading documents from TI and Toshiba, among others on this topic and I appear to be having trouble with the math and cannot figure out why, so I am looking for a little help.
In the document from TI, titled Schottky Diode Selection in Asynchronous Boost Converters, which (obviously) applies to selecting an appropriate SBD, the following is given:

I am following these formulas using the given example values and the result I'm getting is not 0.749A. Here are my results:
\( D = \frac{V_{outmax} - V_{inmin} * efficiency}{V_{outmax}} \)
\( D = \frac{26.7 - 2.7 * 0.87}{26.7} \) \( D = \frac{26.7 - 2.349}{26.7} \) \( D = \frac{24.351}{26.7} \) \( D = 0.912 \)
\( \Delta I_L = \frac{V_{in} * D}{f_{SW} * L} \)
\( \Delta I_L = \frac{26.7 * .912}{1,000,000 * .00001} \) \( \Delta I_L = \frac{24.351}{10} \) \( \Delta I_L = 2.4351\)
\( I_{L(PEAK)} = (\frac{I_{LED(TOTAL)}}{1 - D} + \frac{\Delta I_L}{2}) \)
\( I_{L(PEAK)} = (\frac{.06}{1 - .912} + \frac{2.4351}{2}) \) \( I_{L(PEAK)} = (\frac{.06}{.088} + \frac{2.4351}{2}) \) \( I_{L(PEAK)} = (.6818 + 1.21755) \)
\(I_{L(PEAK)} = 1.9A \)
I'm certain I have to be doing something wrong in my math, I'm so far off from the example result. I want to get the same result as in the example so I'm confident in calculating these values for the circuit I'm currently working on.
Thank you