LAPLACE TRANSFORM HELP (COUPLED SPRING SYSTEM)

Thread Starter

Adanovinivici

Joined Sep 5, 2014
57
Hello All,

Thank you for reading this request. I've come across a laplace transform that I cannot for the life of me correctly take the inverse of. This laplace transform is the solution for the distance of equilibrium of the first mass in an undamped coupled spring system. I'm supposed to obtain a periodic function, but I keep obtaining a hyperbolic cosine. Here is the equation:

F(s)=s*(s^2+2)/(s^4+3*s^2+1)

Please help me understand how I should do this, so I don't go insane. I checked this function with the inverse laplace calculator on wolfram alpha and by some miracle obtained the correct function, so I know this equation is correct but I don't understand why I can't obtain the periodic functions by hand.

Best,
Adanovinivici
 
Last edited:

Jack OwwO

Joined Jun 18, 2015
6
It's just a dumb mistake, when you put back the root of your denominator you forgot the minus sign, \((s^2 - u_1)(s^2 - u_2)\)
Hope you didn't lost too much time on that. rofl.
 
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