kirchoffs law help

Thread Starter

tom6123

Joined May 31, 2014
24
oh so that I2 is going to r2 where as I1 is going towards R1, i didnt know if the current could flow in that direction
 
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shteii01

Joined Feb 19, 2010
4,644
oh so that I2 is going to r2 where as I1 is going towards R1, i didnt know if the current could flow in that direction
My drawing clearly indicate what current goes where.

I don't believe you posted a drawing that shows what you are talking about.
 

Thread Starter

tom6123

Joined May 31, 2014
24
ok i have managed to work out the direction of the currents
- R₄⋅I₁ + 5 - R₁⋅I₁ - R₃⋅(I₁ - I₂) = 0
- R₃⋅(I₂ - I₁) - R₂⋅I₂ - 21 - R₅⋅I₂ = 0

(-R₁ - R₃ - R₄)⋅I₁ + R₃⋅I₂ = -5
R₃⋅I₁ + (-R₂ - R₃ - R₅)⋅I₂ = 21


which came out to I₁=-0.0919505577, I₂=-0.211335544 which are both anticlockwise
how do i work out the current
 

shteii01

Joined Feb 19, 2010
4,644
ok i have managed to work out the direction of the currents
- R₄⋅I₁ + 5 - R₁⋅I₁ - R₃⋅(I₁ - I₂) = 0
- R₃⋅(I₂ - I₁) - R₂⋅I₂ - 21 - R₅⋅I₂ = 0

(-R₁ - R₃ - R₄)⋅I₁ + R₃⋅I₂ = -5
R₃⋅I₁ + (-R₂ - R₃ - R₅)⋅I₂ = 21


which came out to I₁=-0.0919505577, I₂=-0.211335544 which are both anticlockwise
how do i work out the current
The current in R1 and R4 is I1.
The current in R2 and R5 is I2.
The current in R3 is the I1-I2 or I2-I1, notice that numerically they are the same. The difference is the sign, the sign indicates the direction.
 

Thread Starter

tom6123

Joined May 31, 2014
24
Okie dokie so that the current in R3 would be I2-I1.

for the currents going through the resistors would it be acceptable to state them like;
R₁=91.95mA
R₂= 211.34mA
R₃=119.39mA
R₄ = 91.95mA
R₅ = 211.34mA
 

shteii01

Joined Feb 19, 2010
4,644
Okie dokie so that the current in R3 would be I2-I1.

for the currents going through the resistors would it be acceptable to state them like;
R₁=91.95mA
R₂= 211.34mA
R₃=119.39mA
R₄ = 91.95mA
R₅ = 211.34mA
R normally denotes resistance. If you are going to use it to represent current, then I suggest a note in the beginning of your solution that clearly tells your instructor that you will be using letter R to represent current.
 

Thread Starter

tom6123

Joined May 31, 2014
24
IR₁=91.95mA
IR₂= 211.34mA
IR₃=119.39mA
IR₄ = 91.95mA
IR₅ = 211.34mA

is this how you note the current through resistor?
 

shteii01

Joined Feb 19, 2010
4,644
IR₁=91.95mA
IR₂= 211.34mA
IR₃=119.39mA
IR₄ = 91.95mA
IR₅ = 211.34mA

is this how you note the current through resistor?
This would be one way.
Basically you, the person writing the solution, decide how you present your solution. If the instructor/grader does not understand your solution, they will give you zero points and you fail the assignment. It is your responsibility to make sure that person who grades your work can understand the solution you presented.

If your instructor or your textbook uses a certain way to present information, then it makes sense to use their way instead of inventing your own.
 
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Thread Starter

tom6123

Joined May 31, 2014
24
well i will be able to easily indicate what im showing
are the currents correct at first glance. because i dont know if i have to apply them to other calculations

also for the current through resistors
would it be correct to write:
IR₁ is 91.95mA
IR₂ 211.34mA
IR₃ 119.39mA
IR₄ 91.95mA
IR₅ 211.34mA
, or would i have to state it as

IR₁ is-91.95mA
IR₂ -211.34mA
IR₃ 119.39mA
IR₄ 91.95mA
IR₅ 211.34mA
 
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