I was reading through this document
http://www.jensen-transformers.com/wp-content/uploads/2014/08/an002.pdf
the final section has examples of how transformers transforms impedance. I am a little confused.
How to does shorting the primary show 80 ohms on the secondary?
Later, they show more realistic examples, but they say that
If the load were 20k ohms, it would "look like" slightly less than 20k ohms because the open circuit transformer impedance is effectively in parallel with it.
So, if the resistance was closer, the are in series?
I guess it is kind of a bold statement to make with out math to back it up....
Also, since they are 1:1 transformers, wouldn't that mean that it would just see what is there since it is not transforming any impedance?
http://www.jensen-transformers.com/wp-content/uploads/2014/08/an002.pdf
the final section has examples of how transformers transforms impedance. I am a little confused.
How to does shorting the primary show 80 ohms on the secondary?
Later, they show more realistic examples, but they say that
If the load were 20k ohms, it would "look like" slightly less than 20k ohms because the open circuit transformer impedance is effectively in parallel with it.
So, if the resistance was closer, the are in series?
I guess it is kind of a bold statement to make with out math to back it up....
Also, since they are 1:1 transformers, wouldn't that mean that it would just see what is there since it is not transforming any impedance?