Nope.can i know just do the series and bypass r3 to find a total.
Not if it's electron flow.If the top of the 66 volt source is the positive end, as would be usual, the direction of the 1.3 amps is odd.
According to the battery symbol, the top is, indeed, the positive end. The direction is only odd if it is using conventional current, which is why I suspect the course is using electron flow (which should be banished unless it's done correctly, and I've never seen it done correctly yet except by a couple of physicists I've worked with).If the top of the 66 volt source is the positive end, as would be usual, the direction of the 1.3 amps is odd.
Only if the person who drew the diagram followed convention for battery symbols.According to the battery symbol, the top is, indeed, the positive end..
Most of the drawings I've seen tend to get that right. I think Occam's Razor argues in favor of electron current.Only if the person who drew the diagram followed convention for battery symbols.
That is what is throwing me off i think. All of our classes he has taught the current going clockwise and labeled the resistors as so. The arrow pointing in the opposite direction is what throws me off.If the top of the 66 volt source is the positive end, as would be usual, the direction of the 1.3 amps is odd.
If the top of the battery is positive, the current arrow on R3 is wrong for conventional current (if the resistor is an ordinary passive resistor).According to the symbol for the current flow in R3, the diagram is for conventional flow. It would be the other direction for electron flow.
If the top of the battery is positive, the current arrow on R3 is wrong for conventional current (if the resistor is an ordinary passive resistor).
OK. Ignore the arrow for now. What network solving methods have you learned? Can you follow WBahn's suggestion to describe what happens at the upper right hand node?That is what is throwing me off i think. All of our classes he has taught the current going clockwise and labeled the resistors as so. The arrow pointing in the opposite direction is what throws me off.
You can draw the loop arrow in either direction as the direction is completely arbitrary.All of our classes he has taught the current going clockwise and labeled the resistors as so. The arrow pointing in the opposite direction is what throws me off.
Apparently you missed post #17Huh?
Would you agree that the diagram shows the voltage at the top-left node being 66 V higher than the voltage at the bottom-left node?
If so, then would you agree that conventional current flows clockwise around the circuit?
If so, then would you agree that the voltage (relative to the bottom-left node) is lower than 66 V (but greater than 0 V)?
If so, then how is current flowing right-to-left in the bottom resistor consistent with conventional current flow?