10 outputs and 2 clock inputs, plus options like Clock Enable, Carry Out, and Reset.And an 8 pin microcontroller
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10 outputs and 2 clock inputs, plus options like Clock Enable, Carry Out, and Reset.And an 8 pin microcontroller
Sorry I meant 16-pin 8-bit PIC.10 outputs and at least 2 inputs; 3 with Reset.
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So the tradeoff is one cheap micro IC and its required programming versus two cheap digital ICs with no programming.Sorry I meant 16-pin 8-bit PIC.
Example PIC16F15233 is 52 cents at Mouser.
I happen to like programming, it paid the bills for 40 years and left me with a comfortable retirement.So the tradeoff is one cheap micro IC and its required programming versus two cheap digital ICs with no programming.![]()
There are high voltage CMOS versions called CD40192 and CD40193A 74HC192 would do what you want, but it is restricted to a 5 volt maximum supply. You would still need the CD4028 decoder (or similar) to get 10 individual outputs.
Assuming this dream chip is just a part of a larger system, the bent result of using an MCU may well be an overall savings—and a heck of a lot more flexibility.And an 8 pin microcontroller can be had for about 50 cents. Unless you sufferer from fear of programming, it is the simplest solution.
It's not so much liking programming, as how much time/work it would take for the TS to learn how to do it.I happen to like programming
I suppose.IMHO, learning to program microcontrollers is the best investment of time an electronics hobbyist could make.
I guess we are. They may have to bring us back from retirement when they want a logic circuit to work on a 12V supply with 3V of ripple, and don't have room (on the board or in the budget) for a 3.3V regulator and its filter caps.I suppose.
Guess us old analog/discrete-digital types are doomed to extinction.
But I won't give up my op amp, 555, and CD4000 circuits until they pry them from my cold ,dead hands.
Don't have to. Some PICs have them built in,But I won't give up my op amp
Agreed. A “single chip” MCU is only a “single chip” solution if you already have a suitable power supply!It's not clear to me at what voltage the CD4017 will run and what it'll be driving.
I'm contemplating a similar issue using 12V probably and use the CD4017 to drive other CMOS inputs. Then, for up/down counting, the single chip MCU solution becomes 1xMCU, 1x5V regulator plus caps, 1x transistor plus resistors for each output that you need to translate to CMOS high/low.
So this is not to hijack the thread, but to state that depending on requirements the 'single chip' MCU solution is not so obvious to me.
One day they will actually build in a good op-amp!Don't have to. Some PICs have them built in,
Read the OP again. He said he knew how to do it with two ICs, but was looking for a single IC.Two of those CD4xxxx CMOS chips are pretty cheap.
When I started to compose my answer that paragraph was not part of the post. His answers to me also suggested he didn’t know how to do it since he said my suggestion “wouldn’t work”.Read the OP again. He said he knew how to do it with two ICs, but was looking for a single IC.
Maybe @BobTPH could found a system that produces anything from the catalog using PICs and webserial. You just need a pile of pics, and programmer—look up your device and (assuming someone has provided a .bin for it) click on “burn it”, et voila! Instant perfect logic chip.Wikipedia has a list of all the 4000 series devices that have ever lived.
https://en.wikipedia.org/wiki/List_of_4000-series_integrated_circuits
It’s often worth a look through it especially the 401xx and 45xx devices. Then you can be disappointed whe you find exactly the device you need but that it was discontinued aeons ago.
Wasn’t it called a logic array? I have some GAL16V8s, but I don’t have a power supply big enough to run them.Maybe @BobTPH could found a system that produces anything from the catalog using PICs and webserial. You just need a pile of pics, and programmer—look up your device and (assuming someone has provided a .bin for it) click on “burn it”, et voila! Instant perfect logic chip.
I am sure there would be at least… 10… users for such a thing.