hmm..now I'm confused..I verified using circuit simulator and formula and just couldn't seem to get your response.....
I don't think you are right, the series resonant network will look like a capacitor below resonance and inductor above resonance, locally at the resonant frequency, the reactance is almost a straight line. Left side <0, crosses 0, then right side > 0.Don't know what you are using to do these plots, but try using more frequencies. You've got a fairly high Q network with rapid changes in impedance. Checking it only every 0.01 MHz may not be enough.
As I say, I don't know what you are using to do the plotting, but your original plot seems wrong. You have a basic series resonant circuit, which will have a low impedance at resonance. A series resonant network will look like an inductance above it's resonant frequency and C2 will parallel resonate with that inductance. So the impedance plot *should* have an impedance minimum at a lower frequency that the impedance maximum.
That series resonant network will look like a capacitance below resonance. By replacing C2 with L2, you are now resonating that apparent C with L2 producing a parallel resonant circuit -below- the series resonant frequency.
Look closer in with you plotting app, use more frequencies.
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