Hello All and hope all of you are doing great!
I have a question regarding basic control systems.
So i have a transfer function, which is 1 / (s^2 +9s +20) whose inverse Laplace ends up being ( e^-4t) - ( e ^-5t).
Here is my question:
When I designed the transfer function in MATLAB, the output of the scope is as shown below ( with the black background).
When I graphed the Inverse Laplace in a graphing calculator, the graph is as shown below ( with the white background and the blue line).
Why are both graphs not the same? Shouldn't they be the same?
Thank you for your replies.
I have a question regarding basic control systems.
So i have a transfer function, which is 1 / (s^2 +9s +20) whose inverse Laplace ends up being ( e^-4t) - ( e ^-5t).
Here is my question:
When I designed the transfer function in MATLAB, the output of the scope is as shown below ( with the black background).
When I graphed the Inverse Laplace in a graphing calculator, the graph is as shown below ( with the white background and the blue line).
Why are both graphs not the same? Shouldn't they be the same?
Thank you for your replies.
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