Hi everyone!
Could anyone help to answer the question?
Instruction to load register R5 with 20000008 hexadecimal?
LDR R5, #20000008
MOV R5, #0x20000008
LDR R5, =0x20000008
None of the above.
Hi everyone!
Could anyone help to answer the question?
Instruction to load register R5 with 20000008 hexadecimal?
LDR R5, #20000008
MOV R5, #0x20000008
LDR R5, =0x20000008
None of the above.
This question challenges your knowledge and understanding of ARM syntax and architecture.
We can eliminate the first instruction LDR R5, #20000008
since this is not hexadecimal representation.
If you have any knowledge of ARM architecture, you can eliminate the second instruction MOV R5, #0x20000008
since the ARM instruction set cannot generate any random 32-bit literal.
The third instruction LDR R5, =0x20000008
is a pseudo-instruction meaning that there is no single instruction to perform this operation. In this case the assembler will generate a single instruction or multiple instructions in order to achieve this objective.