For the below circuit,


can someone please explain how 1/j became e^(-j*pi/2) in the above equation?

thanks!!

 

Hi solo,
As this is Homework show us your attempt, then we can help.
E

 

Hi Eric,
Thanks for the reply. I was able to figure out the first step as below:

I am stuck after this.

 

\(\frac{1}{j}\;=\;\frac{j}{j^{2}}\;=\;-j\;=\;cos(-\frac{\pi}{2})\;+\;jsin(-\frac{\pi}{2})\;=\;\large{ e^{\frac{-j\pi}{2}}}\)

 

\(\frac{1}{j}\;=\;\frac{j}{j^{2}}\;=\;-j\;=\;cos(-\frac{\pi}{2})\;+\;jsin(-\frac{\pi}{2})\;=\;\large{ e^{\frac{-j\pi}{2}}}\)

Thank you very much!! Greatly appreciate your help!