I can't understand the result of this circuit

Thread Starter

Oussama Zaidi

Joined Mar 1, 2016
Can anyone explain to me how can I get 5V from this circuit?? I simulated it in different programmes and I get the same results but I can't figure why, can anyone explain to me ??


Joined May 19, 2014
Because one end of R4 and R5 are at the same voltage and the other ends are tied together, they are effectively in parallel.

Do you understand this?


Joined Mar 14, 2008
5V across 1kΩ is 5mA
(30V-5V) = 25V across 10kΩ is 2.5mA.
2.5mA +2.5mA = 5mA.
Thus the current through the two 10kΩ resistances balances the current through the 1kΩ resistor as required for the observed voltages.
What did you think the voltage should be?


Joined Apr 3, 2016
If you draw the schematic with V3 and R4 on the right side you can more easily see that the circuit is symmetric about R6. So it becomes obvious that the current through V1 has to be the same as the current through V3. You can also see that both currents meet and flow through R6. So if we call the magnitude of the currents through each voltage source X, then that relationship can be expressed as......

30 - (10K*X) = 1k*2*X

then solve for x

30 - 10KX = 2KX

30= 12KX

X= 30/12K = 2.5 ma


V = 2 * 2.5ma * 1K = 5V