Don't worry about simplifying, just put both into the same standard form and see if they match.I have to show that Y and Z are equal,
Y = (~ABC) + (A~B~C) + (A~BC) + (AB~C) = (~ABC) + (A~C) + (A~B)
But I don't know how to simplify this
Z = (A+B+C) ( A+B+~C) (A+~B+C) (~A+B+C)
How do i start?
(with ~ i mean invert)
okey thanks!Don't worry about simplifying, just put both into the same standard form and see if they match.
This might help: https://forum.allaboutcircuits.com/blog/boolean-logic-sop-and-pos-forms.583/
Consider if you are asked to show that the two expressions:okey thanks!
but how can I do that if I the question is "Show with Boolean algebra that the two expressions are the same."
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