Hi All,
I recently acquired a Fender guitar amp that has a footswitch function. The footswitch has two switches on it, one controls channel select and the other switches FX effect. The interesting part is that the cable to connect the footswitch to the amp can be any guitar cable, that is a cable with a mono jack plug at each end. So how does it control two functions? I found this description in another forum.

I'm no electronics whiz, and I'm a bit confused by the illustration of the jack. It's just a simple mono jack, so what do the numbers 2, 4 and 1 relate to? Or is it just a case of connecting the tip of the jack, i.e. "2" to the diodes and the common switch end to the barrel? Also, I've found elsewhere that the amp supplies 48v AC to the switch. I don't need any leds, so what diode(s) would be appropriate for this circuit?
Thanks,
Ian
I recently acquired a Fender guitar amp that has a footswitch function. The footswitch has two switches on it, one controls channel select and the other switches FX effect. The interesting part is that the cable to connect the footswitch to the amp can be any guitar cable, that is a cable with a mono jack plug at each end. So how does it control two functions? I found this description in another forum.
This schematic was linked to the above.The amp will be sending out an AC signal on a TS jack, and depending on the footswitches selected, it will see either no signal, just the positive half, just the negative half, or the full signal (though slightly modified by the voltage drop across the diode).

I'm no electronics whiz, and I'm a bit confused by the illustration of the jack. It's just a simple mono jack, so what do the numbers 2, 4 and 1 relate to? Or is it just a case of connecting the tip of the jack, i.e. "2" to the diodes and the common switch end to the barrel? Also, I've found elsewhere that the amp supplies 48v AC to the switch. I don't need any leds, so what diode(s) would be appropriate for this circuit?
Thanks,
Ian