
STILL the lower ends of R4 and C4 are shown connected to the batterynegative common instead of the floating common.So I believe trying to drive a relay without a ground connection is problematic.
I see no reason not to use a MOSFET instead.
Below is the simulation of the circuit with a low-power CMOS multivibrator, which significantly reduces the required size of the bootstrap capacitor, C3.
(Note that for proper simulation I had to use an alternate COM icon for the circuit (24V) common because CD4011 uses the triangle ground icon for its common.)
The common BUZ11 MOSFET shown dissipates only about 1/4W in operation, so will get just slightly warm in operation.
Be sure and connect all unused CD4011 inputs to the floating common (triangle) node.
View attachment 190703
As intended.STILL the lower ends of R4 and C4 are shown connected to the batterynegative common instead of the floating common.
The whole point of the thread was that the TS wanted a two terminal circuit because the battery negative connection was not conveniently available. A circuit that utilized the battery ground connection is simple to produce. The original seemed to be intending to replace the old style thermal current driven two terminal flasher, which was a really good design in that it also gave a warning mode when a turn signal bulb failed.As intended.
Those are for the 12V steady supply voltage referenced to battery ground as generated by the LM317.
The bootstrapped 12V referenced to the floating common is Vdd at the diode cathode.
Notice how Vdd referenced to the battery ground (blue trace) rises to near 36V when the lamp is on.
And since the 4011 is a quad nor gate all 3 sections in parallel can be used to drive the FET, since the gate is a capacitive load, and since the unused inputs need to be tied someplace no matter what. And this circuit is elegant in it's simplicity.
Duh!The whole point of the thread was that the TS wanted a two terminal circuit because the battery negative connection was not conveniently available.
Yes, that should work.How about something like this:

Hello
I want to drive the relay in the following circuit.
Here the ground is not directly connected to the circuit.
It is connected to the ground through the lamp and the lamp is connected to the relay output.
But the circuit has a problem.And the irregular relay is disconnected and connected.View attachment 190515
How should I drive this relay?
Are circuits that are not directly connected to the earth have a special name?
Did you look at the solution in post #31?Several solutions do come to mind.
Also those big Diesel engines are difficult to start with a 12V starter in cold weather.you save a lot of copper going to 24 Volts.
You brought up a good point.I'm sure post 31 would blink on the first blink
