How does it work ? ---thread

Thread Starter

Externet

Joined Nov 29, 2005
2,631
Thanks, Bertus.
My german is not good enough to follow that site and learn if those attenuators being all? 50 ohm? berilium? ceramic resistors? ; how they present (5) different attenuation choices or they are several Ohm flavors.
I was looking for 50 Ohm dummy load RF resistor loads when stumbled to the post #8 head scratcher.

In that german site; they show a 50 Ohm load being 40dB attenuation:

1734607829987.png
1734607761718.png
And other all 50 Ohm? with several attenuation choices:

1734608112730.png
 
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Thread Starter

Externet

Joined Nov 29, 2005
2,631
Perhaps am answering myself: I can see this is "in-line" "in series" coaxial attenuator [resistive network inside]

1734608439548.png


and this is a termination load; [single resistor load inside] :
1734608651048.png
 

bertus

Joined Apr 5, 2008
22,922
Hello,

The white resistior like attenuator is likely to be symetric, so it does not matter wich is the in or output.
The encased attenuators are most times asymetric, so take care of in and output.

When you terminate the 40 dB attenuator with 50 ohms, it will become a dummyload.
You can use the 40 dB output also to connect to a scope with 50 ohm input.
That way you can measure powers.
Never put any power at the 40 dB attennuator output, it will damage the device.

Bertus
 
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