Homogeneous Equations
- Thread starter full
- Start date
Your strategy is correct, but
Look again at your integration line.
\(\int {\frac{{dv}}{{{v^3}}}} + \int {\frac{{dv}}{v}} \)
is not what you have.
You add +1 to the index when you integrate or take the ln if the index is -1
When you have the correct general solution you should be able to substitute back for v = y/x to obtain the general solution in terms of the original variables.
Then it is a matter of applying the initial condition y(0)=2
Look again at your integration line.
\(\int {\frac{{dv}}{{{v^3}}}} + \int {\frac{{dv}}{v}} \)
is not what you have.
You add +1 to the index when you integrate or take the ln if the index is -1
When you have the correct general solution you should be able to substitute back for v = y/x to obtain the general solution in terms of the original variables.
Then it is a matter of applying the initial condition y(0)=2
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