# Homogeneous Equations

Discussion in 'Math' started by full, Sep 28, 2014.

1. ### full Thread Starter Member

May 3, 2014
225
2
Hello everyone,
I do this problem from Homogeneous Equations ......
and how I know my answer is true?
thanks

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2. ### studiot AAC Fanatic!

Nov 9, 2007
5,005
516

Look again at your integration line.

$\int {\frac{{dv}}{{{v^3}}}} + \int {\frac{{dv}}{v}}$

is not what you have.

You add +1 to the index when you integrate or take the ln if the index is -1

When you have the correct general solution you should be able to substitute back for v = y/x to obtain the general solution in terms of the original variables.
Then it is a matter of applying the initial condition y(0)=2

Last edited: Sep 28, 2014
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