First of all, i would like to thanks for the developer of this website especially the forum section. I am new to digital logics and design. Our teacher has given homework to simplify the booleon algebric expression to specific literals; i tried alot and able to solve just one out of them. Can someone help me and solve this for me.
I am trying for last one week, though i know and learnt the laws like commutative, distributive, assosiative, but still i can not find the way to proceed. The one i solved is:
A: Simplify the expession to the said literals:
1. ABC + A'B'C + A'BC + ABC' + A'B'C' to five literals
=>ABC + ABC' + A'B'C + A'B'C' + A'BC
=>AB(C+C') + A'B'(C+C') + A'BC
=>AB(1) + A'B'(1) + A'BC
=>AB + A'B' + A'BC
=>AB + A'(B' + BC)
=>AB + A'(B' + B)(B' + C)
=>AB + A'(1)(B' + C)
=>AB + A'(B' + C) ------------- Answer
Hereby u are request to help me in question 2 to 8 which are as following:
2. BC + AC' + AB + BCD to four literals
3. [(CD)' +A]' + A + CD + AB
4. (A + C + D)(A + C + D')(A + C' + D)(A + B')
B: First take the complement and then reduce the expression to minimum literals possible:
1. (BC' + A'D)(AB' + CD')
2. B'D + A'BC' + ACD + A'BC
3. [(AB)'A][(AB)'B]
4. AB' + C'D'
I will highly appriciate your kind help. thanks
I am trying for last one week, though i know and learnt the laws like commutative, distributive, assosiative, but still i can not find the way to proceed. The one i solved is:
A: Simplify the expession to the said literals:
1. ABC + A'B'C + A'BC + ABC' + A'B'C' to five literals
=>ABC + ABC' + A'B'C + A'B'C' + A'BC
=>AB(C+C') + A'B'(C+C') + A'BC
=>AB(1) + A'B'(1) + A'BC
=>AB + A'B' + A'BC
=>AB + A'(B' + BC)
=>AB + A'(B' + B)(B' + C)
=>AB + A'(1)(B' + C)
=>AB + A'(B' + C) ------------- Answer
Hereby u are request to help me in question 2 to 8 which are as following:
2. BC + AC' + AB + BCD to four literals
3. [(CD)' +A]' + A + CD + AB
4. (A + C + D)(A + C + D')(A + C' + D)(A + B')
B: First take the complement and then reduce the expression to minimum literals possible:
1. (BC' + A'D)(AB' + CD')
2. B'D + A'BC' + ACD + A'BC
3. [(AB)'A][(AB)'B]
4. AB' + C'D'
I will highly appriciate your kind help. thanks