I am trying for last one week, though i know and learnt the laws like commutative, distributive, assosiative, but still i can not find the way to proceed. The one i solved is:

A: Simplify the expession to the said literals:

1. ABC + A'B'C + A'BC + ABC' + A'B'C' to five literals

=>ABC + ABC' + A'B'C + A'B'C' + A'BC

=>AB(C+C') + A'B'(C+C') + A'BC

=>AB(1) + A'B'(1) + A'BC

=>AB + A'B' + A'BC

=>AB + A'(B' + BC)

=>AB + A'(B' + B)(B' + C)

=>AB + A'(1)(B' + C)

=>AB + A'(B' + C) ------------- Answer

Hereby u are request to help me in question 2 to 8 which are as following:

2. BC + AC' + AB + BCD to four literals

3. [(CD)' +A]' + A + CD + AB

4. (A + C + D)(A + C + D')(A + C' + D)(A + B')

B: First take the complement and then reduce the expression to minimum literals possible:

1. (BC' + A'D)(AB' + CD')

2. B'D + A'BC' + ACD + A'BC

3. [(AB)'A][(AB)'B]

4. AB' + C'D'

I will highly appriciate your kind help. thanks