Your question is incomplete. We need to know what input voltage you are working with and your goal for efficiency. When it comes to efficiency, this will be a tradeoff between efficiency and cost. Once you go above 90% each incremental improvement requires a disproportionate increase in expense. You also did not indicate if this will be a purchased item or one that you design and construct.Hello!
I'm developing BMS 30S based on stm32L with CAN interface. It uses 10mA in an run mode (95% time) and sometimes up to 100 mA.
Which is buck converter better to use in my case for the most efficiency?
Thanks)))
Given that you have multiple battery configurations, and various states of discharge on the cells. You want a DC-DC converter that will output 3.3V if the input is between 2.5V and 21V (5 x 4.2), is that correct?MIC23050 and the MIC2285 has input voltage 2.7V...5.5V. But min voltage of discharged battery is 2.5. And would not like to use one cell
2.5×5=12.5V to 4.2×5=21V.Given that you have multiple battery configurations, and various states of discharge on the cells. You want a DC-DC converter that will output 3.3V if the input is between 2.5V and 21V (5 x 4.2), is that correct?
Once you pick a particular cell count, will you stick with that configuration or will you be changing it?2.5×5=12.5V to 4.2×5=21V.
But i can use any cell count from 3 to 30
no, battery pack has 30S and will not change.Once you pick a particular cell count, will you stick with that configuration or will you be changing it?
I have 30S in my battery pack. But i can to use less of 30S for converterI did not see you wanted to use up to 30 batteries.
If the input is below the output then we need a "buck/boost".
OK. How about these:I have 30S in my battery pack. But i can to use less of 30S for converter
It is inadvisable to connect to fewer cells than the whole battery pack if the entire battery pack connects to a single charger.I have 30S in my battery pack. But i can to use less of 30S for converter
Because that will discharge some cells more than others, which runs a risk of overcharging the ones that have been under discharged.why?
On what basis do you make this claim? Is it your position that the chip (LM2596) cannot be used in a converter with greater than 75% efficiency? I think it has more to do with the other components than the chip itself.The LM2596 has less of 75% efficiency))
And i need chip, not module
Doesn't that mean that it partially discharges some cells whilst it is waiting for the others to get fully charged? Won't it extend the charge time?BMS has ballasing.
I would like to use 30S but it is to much for converter