i have a four input circuit, and so far i have these equations down but im not sure how to simplify it more if i can. this is the truth table:

ABCD F
0000 |1
0001 |1
0010 |0
0011 |1
0100 |1
0101 |1
0110 |1
0111 |1
1000 |1
1001 |1
1010 |1
1011 |1
1100 |0
1101 |1
1110 |0
1111 |0

so far i have this:

(ABC)' (A' + B' + D)(A + B + C' + D)

any help would be appreciated. Im pretty sure the the last 2 might factor out a D and maybe make an xor gate out of the A and B but im not for sure. Also if anyone has any links to threads on here or elsewhere there would be a good place to help practice making schematics or tips on making schematics please share. I'm good at normal schematics, but now I'm working on a 7 segment display so i have 7 outputs, and I'm having trouble with combining all my work into one thing.
Thank you for your time

 

Review the section in the AAC ebook on POS and SOP boolean algebra.

hgmjr

 

thank you.


btw my equations are wrong on the first part, its actually:


(A' + B' + C')(A' + B' + D)(A + B + C' + D)

 

shawd,

You should read this link and download the program referenced in it. http://forum.allaboutcircuits.com/showthread.php?t=27872 . Then you can tell if your expressions are equivalent. In this case, your solution is. Since you did not explain how you arrived at your solution, and I did not do the problem, I cannot say that you have the simplest POS expression. See if this link helps you out. http://forum.allaboutcircuits.com/showthread.php?t=12279&highlight=POS+Boolean

Ratch