Hello everyone! I am new to this forum but am glad I found it. I have a pretty good understanding of troubleshooting and analyzing circuits, but the one I am currently working on is proving a bit difficult, especially sense my book does a terrible job at explaining how to do this.
Anyhow, here is my assignment:
An RC low-pass filter has the following exact values: RF = 100 Ω, RS = 50 Ω, and CF = 10 μF. The filter is connected to a load that can vary over a range of 10 to 500 Ω. Calculate:
The range of Av for the circuit.
The range of fC for the circuit.
So, I know the formula for Av(max) = Req/(Req)+(Rs)
and I also know that Req = Rp || RL
However, I am lost as how to get started because, for one thing, I do not see a value for RL listed. Furthermore to find Rp, I would need to find Q, but to find Q I would need to calculate XL and again, no value is presented for an inductor.
Perhaps I am just looking at this assignment the wrong way?
Any advice would be greatly appreciated! Thanks in advance!
- ParaTrooperJoe -
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Here is what I think is the correct way to approach this.
Once I reread the question, I see that the load (RL) ranges from 10 to 500 ohms (DOH!)
So:
A:
When RL = 10Ω -
AV(max) = R_L/(R_L+R_F ) = 10Ω/(10Ω+100Ω) = 0.0909
When RL = 500Ω -
AV(max) = R_L/(R_L+R_F ) = 500Ω/(500Ω+100Ω) = 0.833
B:
When RL = 10Ω -
First, I calculated the value of R while RL = 10Ω:
R1 = 1/(1/Rf +1/RL1 +1/Rs ) = 1/(1/100+1/10+1/50) = 7.69
fc = 1/(2π(R1)(C)) = 1/(2π(7.69)(10µF)) = 2.07 kHz
When RL = 500Ω -
First, I calculated the value of R while RL = 500Ω:
R2 = 1/(1/Rf +1/RL2 +1/Rs ) = 1/(1/100+1/500+1/50) = 31.25
fc = 1/(2π(R2)(C)) = 1/(2π(31.25)(10µF)) = 509.3 Hz
I think that makes more sense, and hopefully I have done these calculations correct. If anyone has any advice to offer, I would greatly appreciate it!
Anyhow, here is my assignment:
An RC low-pass filter has the following exact values: RF = 100 Ω, RS = 50 Ω, and CF = 10 μF. The filter is connected to a load that can vary over a range of 10 to 500 Ω. Calculate:
The range of Av for the circuit.
The range of fC for the circuit.
So, I know the formula for Av(max) = Req/(Req)+(Rs)
and I also know that Req = Rp || RL
However, I am lost as how to get started because, for one thing, I do not see a value for RL listed. Furthermore to find Rp, I would need to find Q, but to find Q I would need to calculate XL and again, no value is presented for an inductor.
Perhaps I am just looking at this assignment the wrong way?
Any advice would be greatly appreciated! Thanks in advance!
- ParaTrooperJoe -
***************************************************
Here is what I think is the correct way to approach this.
Once I reread the question, I see that the load (RL) ranges from 10 to 500 ohms (DOH!)
So:
A:
When RL = 10Ω -
AV(max) = R_L/(R_L+R_F ) = 10Ω/(10Ω+100Ω) = 0.0909
When RL = 500Ω -
AV(max) = R_L/(R_L+R_F ) = 500Ω/(500Ω+100Ω) = 0.833
B:
When RL = 10Ω -
First, I calculated the value of R while RL = 10Ω:
R1 = 1/(1/Rf +1/RL1 +1/Rs ) = 1/(1/100+1/10+1/50) = 7.69
fc = 1/(2π(R1)(C)) = 1/(2π(7.69)(10µF)) = 2.07 kHz
When RL = 500Ω -
First, I calculated the value of R while RL = 500Ω:
R2 = 1/(1/Rf +1/RL2 +1/Rs ) = 1/(1/100+1/500+1/50) = 31.25
fc = 1/(2π(R2)(C)) = 1/(2π(31.25)(10µF)) = 509.3 Hz
I think that makes more sense, and hopefully I have done these calculations correct. If anyone has any advice to offer, I would greatly appreciate it!