Help with Basic Circuits

Thread Starter

RUSTYWIRE

Joined Aug 28, 2023
113
Ohms Law not working.

I have a very basic breadboard circuit with a 1.5 (reads 1.6) volt alkaline battery, and 10 Ohm, 1% resistor, (reads 10.1 ohms)
I will expand it with more components as I prove out steps in Ohms Law.

According to the law, I should be measuring 160 ma current. Instead I am getting 125 ma. I checked for any additional resistance in the components
but all check out OK. I am using a $100 digital multimeter.

Why am I not getting 160 ma?

Thanks
 

djsfantasi

Joined Apr 11, 2010
9,237
How did you measure the battery voltage? Was it in-circuit (10Ω resistor connected) or standalone? Under load, the voltage from a battery will drop.

Given your results, I’d expect that under load, the battery voltage will read about 1.25V.
 

Thread Starter

RUSTYWIRE

Joined Aug 28, 2023
113
How did you measure the battery voltage? Was it in-circuit (10Ω resistor connected) or standalone? Under load, the voltage from a battery will drop.

Given your results, I’d expect that under load, the battery voltage will read about 1.25V.
Hold on let me check now.

With the resistor the voltage is reading 1.47 across R and 1.53 across the cell.
 
Last edited:

Thread Starter

RUSTYWIRE

Joined Aug 28, 2023
113
The is a huge difference between a weak small AAA battery cell and a powerful D size battery cell.
It's a AA.

I'm just going over elementary projects and happen to have a lot of AA alkalines with holders just to observe different scenarios with cells & batteries.
 

Audioguru again

Joined Oct 21, 2019
6,826
You must measure the voltage across the resistor while it it is being heated by the battery cell.
1.6V x 160mA= 256mW then a 1/4W resistor gets too hot so use a 1/2W or larger resistor.
 

dl324

Joined Mar 30, 2015
18,220
According to the law, I should be measuring 160 ma current. Instead I am getting 125 ma. I checked for any additional resistance in the components
I can guarantee you that Ohm's law is working and this is operator error. The ammeter is perturbing the circuit. What is the meter's burden voltage?
 

boostbuck

Joined Oct 5, 2017
1,034
Is the 10.1 Ohm measurement including the resistance of the meter leads? Does your meter have a 'relative' setting to zero out the leads?

Since your resistor is 1%, measuring the VOLTAGE across the resistor and using ohms law will give you a close true value for the current in the circuit. As mentioned above, the meter's amp range burden voltage is likely to cause errors in a low voltage circuit when measuring current in-circuit.
 

KL7AJ72

Joined Apr 15, 2021
22
Ohms Law not working.

I have a very basic breadboard circuit with a 1.5 (reads 1.6) volt alkaline battery, and 10 Ohm, 1% resistor, (reads 10.1 ohms)
I will expand it with more components as I prove out steps in Ohms Law.

According to the law, I should be measuring 160 ma current. Instead I am getting 125 ma. I checked for any additional resistance in the components
but all check out OK. I am using a $100 digital multimeter.

Why am I not getting 160 ma?

Thanks
10 ohms is pretty low resistance, you're probably loading down your battery too much. Try 100 ohms and look for 16ma
 

Thread Starter

RUSTYWIRE

Joined Aug 28, 2023
113
So how do you determine " the meter's amp range burden voltage"?

In the meantime I'll get the manual and check.

Thanks
 

Thread Starter

RUSTYWIRE

Joined Aug 28, 2023
113
The 100 ohm resistor is reading 154 ma good but trying to locate the missing 6 ma is interesting for learning.

No doubt its taken up somewhere in the hardware, but where? No big deal except for learning.

Also I would like to know the burden voltage for my meter for general purposes if anyone know how to determine that?

Additionally, knowing the internal resistance of the 1.5 (1.6) V cell.

This is all a foundation for future circuits.

Thanks
 

MrChips

Joined Oct 2, 2009
34,628
All meters have resistance. What is the resistance of the ammeter?
From your data, you can calculate the resistance of the meter.
 
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