Yes i want to use both. So i either wanna switch on/off the LEDs (and also power the esp) using the switch. Furthermore it should be possible to control the spotlight with the app.

Why do you want to use "both?" What do you mean by both? Can you draw a truth table showing the switches you want to use, the state of each (i.e., on or off) , the corresponding state of each of the LED's, and the state of your ESP/BT modules?

What spotlight?

If all you want to do is turn on the LED's when ESP/BT are off, then just wire a switch(s) as an OR, e.g., with diode logic (aka diode resistor logic)(https://en.wikipedia.org/wiki/Diode_logic ). Your origin post looked like it was headed in that direction, then things got confusing.

 

Ok the truth table is probably a good idea.



Furthermore here is my updated scheme, i switched to an esp32 so i dont need an extra bluetooth module.

 

Yes i want to use both. So i either wanna switch on/off the LEDs (and also power the esp) using the switch. Furthermore it should be possible to control the spotlight with the app.

Maybe I wasn’t clear. I am suggesting that local input to the MCU would allow operation parallel to the app.
Switching the power at the batteries would be separate. Turn off the power, nothing works. Turn it on, use the app or use a momentary switch to tell the MCU to turn on the lights.

Are you trying to avoid using the MCU? If so, why?

 

@pelzigan
That's getting there, but how do you explain this (just one example):

 

@pelzigan
That's getting there, but how do you explain this (just one example):
View attachment 174495

Looking at the scheme it makes sense. The FET may be open but there is no power on the LED1 & 2 so they are turned off. It makes no sense to include this line in the truth table, but i wanted it to be complete. ^^

 

OK, I see it. Switch position 1 = FETs only control 3&4 (1&2 are always off ). In position 2, FETs control all LED's (in pairs), and position 3 all are off.

 

OK, I see some of it. Switch position 1 = FETs only control 3&4. In position 2, FETs control all LED's (in pairs), and position 3 all are off.

exactly.