Help on max/min. excursion in amplifier

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dsp_redux

Joined Apr 11, 2009
182
Hi, I'm having trouble finding the theorical max/min. excursion limits \(v_{o_{(+)}}\) and \( v_{o_{(-)}}\) on the figure below. Could someone help me on this? I know that
\(\begin{gather}
v_{DG_{2}} \geq -V_{THN} = -1.85V\\
v_{out} + V_{OUT} - (15V - RI_{BIAS}) = -1.85V\\
\text{With $R=1.5k\Omega$ and $I_{BIAS}=8mA$}\\
v_{o_{(-)}} = 1.15V
\end{gather}\)
Could you 1. verify the equations above and 2. how do I calculate the other limit?
 

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mik3

Joined Feb 4, 2008
4,843
Assuming ideal components, the maximum positive voltage is 15V and the minimum is 0.8V if the bias current is 8mA.
 
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