# Help on max/min. excursion in amplifier

Discussion in 'Homework Help' started by dsp_redux, Feb 7, 2010.

1. ### dsp_redux Thread Starter Active Member

Apr 11, 2009
182
5
Hi, I'm having trouble finding the theorical max/min. excursion limits $v_{o_{(+)}}$ and $v_{o_{(-)}}$ on the figure below. Could someone help me on this? I know that
$\begin{gather}
v_{DG_{2}} \geq -V_{THN} = -1.85V\\
v_{out} + V_{OUT} - (15V - RI_{BIAS}) = -1.85V\\
\text{With R=1.5k\Omega and I_{BIAS}=8mA}\\
v_{o_{(-)}} = 1.15V
\end{gather}$

Could you 1. verify the equations above and 2. how do I calculate the other limit?

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2. ### mik3 Senior Member

Feb 4, 2008
4,846
68
Assuming ideal components, the maximum positive voltage is 15V and the minimum is 0.8V if the bias current is 8mA.