Help on max/min. excursion in amplifier

Discussion in 'Homework Help' started by dsp_redux, Feb 7, 2010.

  1. dsp_redux

    Thread Starter Active Member

    Apr 11, 2009
    Hi, I'm having trouble finding the theorical max/min. excursion limits v_{o_{(+)}} and  v_{o_{(-)}} on the figure below. Could someone help me on this? I know that
    \begin{gather}<br />
v_{DG_{2}} \geq -V_{THN} = -1.85V\\<br />
v_{out} + V_{OUT} - (15V - RI_{BIAS}) = -1.85V\\<br />
\text{With $R=1.5k\Omega$ and $I_{BIAS}=8mA$}\\<br />
v_{o_{(-)}} = 1.15V<br />
    Could you 1. verify the equations above and 2. how do I calculate the other limit?
  2. mik3

    Senior Member

    Feb 4, 2008
    Assuming ideal components, the maximum positive voltage is 15V and the minimum is 0.8V if the bias current is 8mA.